Math, asked by Hina561, 11 months ago

Q.Find the area enclosed by the following figures:
PlZ PLZ PLZ YRR HELP ME IN THIS PLZ.........​

Attachments:

Answers

Answered by rajshreemishra81
0

Answer:

Step-by-step explanation:

Area of the figure = area of UARQ + area of RESQ

Area if UARQ = l × b (as it is a rectangle )

Area = 22 × 16 = 352cm^2

Area of trapezium RESQ =sum of parallel sides/2 × height

Height of trapezium = 30cm - 22cm

= 8 cm

We found the height by subtracting the length of the rectangle (22cm)from the total length of the figure ( 30cm ) .

RQ = UA ( opposite sides of rectangle are equal )

RQ=16 cm

Area of trapezium = ( 8+ 16)/2 × 8

= 96cm^2

Total area of the figure = area of rectangle + the area of teh trapezium

= 352cm^2 + 96cm ^2

= 448cm ^2

Hope this helps you.

Similar questions