Q.Find the area enclosed by the following figures:
PlZ PLZ PLZ YRR HELP ME IN THIS PLZ.........
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Answer:
Step-by-step explanation:
Area of the figure = area of UARQ + area of RESQ
Area if UARQ = l × b (as it is a rectangle )
Area = 22 × 16 = 352cm^2
Area of trapezium RESQ =sum of parallel sides/2 × height
Height of trapezium = 30cm - 22cm
= 8 cm
We found the height by subtracting the length of the rectangle (22cm)from the total length of the figure ( 30cm ) .
RQ = UA ( opposite sides of rectangle are equal )
RQ=16 cm
Area of trapezium = ( 8+ 16)/2 × 8
= 96cm^2
Total area of the figure = area of rectangle + the area of teh trapezium
= 352cm^2 + 96cm ^2
= 448cm ^2
Hope this helps you.
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