Q.Find the area of the shaded region. Given, ABCD is a square of side 28cm. BPC is a semi-circle & APD is
triangle?
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1
Answer:
answer = 378
Step-by-step explanation:
a^2 = 784
area of semi circle = 308
area of triangle = 98
so shaded area = 784-308-98 = 378
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3
area of shaded region= area of square-(area of semicircle+area of triangle)
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