Q Find the area of the shaded region, where O is the center of the circle
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Given, AC = 24 cm and BC = 10 cm Since, AB is the diameter of the circle Angle ACB = 90o So, using Pythagoras theorem AB2 = AC2 + BC2 = 242 + 102 = 576 + 100 = 676 AB = √676 = 26 cm Thus, the radius of the circle = 26/2 = 13 cm The area of shaded region = Area of semi-circle – Area of triangle ACB = 1/2 πr2 – 1/2 x b x h = 1/2 (22/7)132 – 1/2 x 10 x 24 = 265.33 – 120 = 145.33 cm2Read more on Sarthaks.com - https://www.sarthaks.com/661687/find-the-area-of-the-shaded-region-in-fig-if-ac-24-cm-bc-10-cm-and-o-is-the-center-of-the-circle
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