Question

Q. Find the area of trapezium where length of parallel sides are 15 cm and 25 cm and the third side measures 12 cm.

I am ot7 ​

Answer 1

A=a+b

2h

a Base

15

cm

b Base

25

cm

h Height

Enter value

if you got it right mark as brainlist

Answer 2

Answer:

AE=DC=13cm and BE=AB−AE=25−13=12cmIn ΔBCE, we have s= 215+15+12 =21cm∴ Area of ΔBCE= s(s−a)(s−b)(s−c) ⇒ Area of ΔBCE= 21(21−15)(21−15)(21−12) = 21×6×6×9 =18 21

Hope it helps you:)