Q
Find the equation of a line lies
on a plane
plane 2x-3y + 4z=-8,
perpendicular to a line
x-1/3=y-1/2=z-2/3 and passes through
the points (1,2,-1),
Answers
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Answer:
No such line can exist because the point
(1,2,−1) does not lie on the plane 2x−3y+4z=8
, therefore, the line cannot lie on the plane.
Step-by-step explanation:
An additional reason why no such line can exist is that the direction of the line is
→l=3ˆi+2ˆj+3ˆk
; this means that the only planes that can have lines that intersect the given line perpendicularly must be of the form 3x+2y+3z=c where c is any real number. All other planes cannot have lines that intersect the given line perpendicularly.
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