Q} Find the equation of straight line passing through the points (4,5) and equally inclined to the line 3x=4y+7 and 5y=12x+6.
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m=5-(-4)÷(-12)-3
m=9÷(-15)
m=(-3/5)
(Y-Y1)=m(X-X1)
y-5=(-3/5)(x-4)
5y-25= -3x+20
3x+5y=45
i hope this will help you
m=9÷(-15)
m=(-3/5)
(Y-Y1)=m(X-X1)
y-5=(-3/5)(x-4)
5y-25= -3x+20
3x+5y=45
i hope this will help you
dAsh7:
But only the equations are given to which the line is inclined equally
Ad if you take out the value pf x and y from the equations... Then
No problem..
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