Question

Q. Find the HCF of 65 and 117 and find a pair of integral values of m and n such that HCF = 65m + 117n.
Please help it's urgent
Ch - Real Numbers
Class X
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Answer 1

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Step-by-step explanation:

By Euclid's division algorithm

=117=65×1+52→(1)

=65=52×1+13→(2)

=52=13×4+0→(3)

Therefore 13 is HCF f (65,117)

Now going backward

=13=65+52×(−1)

=13=65+[117−65×1]×(−1) [From (1)]

=13=65×2+117×(−1)

=∴m=2n=−1

$\pink{i \: hope \: it \: helpfull \: for \: you}$

Answer 2

Answer:

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