Question

Q. Find the last digit of the number
( 1^3 + 2^3 + 3^3 + ... + 99^3 )​

Answer 1

Answer:

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Step-by-step explanation:

Last digit is the remainder when(1!+2!+3!+⋯+33!)33is divided by 10

1!=12!=23!=64!=245!=1206!=720

7!=5040

1!+2!+3!+4!=1+2+6+24=33

What we observed that the unit digit of all factorials starting from 5! upto