Q. Find the least number which when divided by 25 , 40 and 60 leaves and 9 as the remainder in each case .
PLEASE tell the answer it's urgent .
Who will give the right answer whom I will be mark as BRAINLIST.
PROMISE.
Answers
Answered by
3
Answer:
If the required number is , then leaves a remainder of 0 when divided by 25, 40 and 60.
Any multiple of their lowest common multiple will leave a remainder of 0.
Their LCM is 600.
Answered by
2
Answer:
609
Step-by-step explanation:
Clearly the required no = LCM(25,40,60) +9
Now,. 25 = 5×5 = 5²
40 = 2×2×2×5 = 2³×5
60 = 2×2×3×5 = 2²×3×5
LCM = highest power of all factors = 5²×2³×3
= 600
Hence, the required no. = 600+9 = 609
Mark brainliest and follow if interested in maths and science
Similar questions