Question

Q. Find the measure of each angle of a parallelogram if its larger angle is 30° less than twice the smaller angle.

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Hint : The answer should be 70°,70°,110°,110°
please right answer bata dijiye​

Answer 1

Step-by-step explanation:

see the attached image

hope it help u

Answer 2

Correct option is D -70° ,110° ,70° ,110°

angles are x° (2x−30),x,(2x−30)

sum of angles of ∥ gm is 360°

⇒x+(2x−30)+x+(2x−30)=360°

x+(2x−30)++x(2x−30)=360°

⇒6x=420⇒$\fbox{x=70}$

$\tt\fbox{⇒Angles are⇒70°, 110°, 70°, 110°}$

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