Question

Q: Find the molarity obtained by 54 gm hno3 is dissolved in 450 ml of water?

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Answer 1

${\Large{\bf{Given}}}\begin{cases}\longrightarrow Given \:weight\: of \:HNO_{3}=54g\\ \longrightarrow Volume \:of \:water =450ml \end{cases}$

So, Molecular weight of $HNO_{3}$ = 1+14+16×3=15+48=63gm.

Now,

No. of moles =$\dfrac{Given\:Weight}{Molecular\:weight}$

$\implies n =\dfrac{54g}{63g}$

$\implies n =\dfrac{\cancel{54g}^{6}}{\cancel{63g}^{7}}$

${\underline{\boxed{\red{.\degree. n =\dfrac{6}{7}}}}}$

Now, volume is 450 ml = $\dfrac{450L}{1000}$

____________________________________

So,

$\Large\orange{\boxed{\purple{M=\dfrac{n}{V(in \:L)}}}}$

where

• M is molarity of solution.

$\implies M =\dfrac{6}{7\times \dfrac{450}{1000}}$

$\implies M =\dfrac{6\times 1000}{7\times 450}$

$\implies M =\dfrac{\cancel{6}^{2}\times 100\cancel{0}}{7\times \cancel{45\cancel{0}}^{15}}$

$\implies M =\dfrac{200}{105}$

${\underline{\boxed{\purple{.\degree. M =1.90}}}}$