Question

Q.Find the point on the x-axis which is equidistant from (2,-5) and (-2,9).

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Answer 1

Step-by-step explanation:

Since point on x−axis, then coordinate of the point is (x,0). 

According to the question this point (x,0) is equidistant from the points (2,−5) and (−2,9).

That is, distance from  (x,0) and (2,−5) = distance from (x,0) and (−2,9).

(2−x)2+(−5−0)2=(−2−x)2+(9−0)2⇒(2−x)2+(−5)2=(−2−x)2+(9)2⇒4−4x+x2+25=4+4x+4+81⇒8x=25−81⇒8x=−56⇒x=−7

So, point is (−7,0).