Question

Q. Find the smallest no. which when increase by 17 exactly divisible 560 and 420 ​

Answer 1

Answer:

Step-by-step explanation:

Small number divisible by 520 and 468 when it is increased by 17 is 4663

Solution:

To find smallest number dividing both 520 and 468 when increased by 17, can be found out by LCM method

LCM of 520 and 468 =  

Now the total value that is to be divided or the smallest number after increase by 17 becomes 4680, therefore the smallest number will be,

4680 – 17 = 4663

Therefore the number after subtraction of 17 becomes 4663