Q. Find the square root of 2-2√3i
Answers
Answered by
3
Answer:
the correct answer is 58
Answered by
0
Answer:
le (2+2
3
i)
1/2
=x+iy
sq. both side
2+2
3
i=x
2
−y
2
+2xyi
⇒x
2
−y
2
=2−−−−(i) & xy=
3
−−−−(ii)
we know
(x
2
+y
2
)
2
=(x
2
−y
2
)
2
+(2xy)
2
=2
2
+(2
3
)
2
=16
x
2
+y
2
=4−−−−(iii)
Solve (i) & (iii) from (2) & (iii)
2x
2
=16 2xy=2
3
x=±
3
x=±
3
∴ ⇒y=±1
Then,
(2+2
3
i)
1/2
=±(
3
+i)
Step-by-step explanation:
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