Math, asked by aditisrivastava2869, 20 hours ago

Q.
Find the time period when 6250 yields an
amount of 7873.20 at 8% per annum
compounded anually. ​

Answers

Answered by pintoalex
0

Answer:

Step-by-step explanation:Following is the formula for calculating compound interest when time period is specified in years and interest rate in % per annum.

A = P(1+r/n)nt

CI = A-P

Where,

CI = Compounded interest

A = Final amount

P = Principal

t = Time period in years

n = Number of compounding periods per year

r = Interest rate

Calculation Examples

You can solve for any variable by rearranging the compound interest formula as illustrated in the following examples:-

1. What is the compound interest of 75000 at 7.9% per annum compounded semi-annually in 3 years?

Ans. A = P(1+r/n)nt = 75000(1 + (7.9 / 100) / 2)6 = 94625.51

Interest = 94625.51 - 75000 = 19625.51

2. In how many years will a amount double itself at 10% interest rate compounded quarterly?

Ans. t = (log(A/P) / log(1+r/n)) / n = log(2) / log(1 + 0.1 / 4) / 4 = 7.02 years

3. If interest is compounded daily, find the rate at which an amount doubles itself in 5 years?

Ans. r = ((A/P)1/nt - 1) × n = (21/(365×5) - 1) × 365 = 0.13865 = 13.87% per annum

4. What is the present value of 500 to be paid in two years if the interest rate is 5 percent compounded annually?

Ans. P = A/(1+r/n)nt = 500/(1+5/100)2 = 453.51

Answered by thirukumaranmrv7a4
0

Answer:

3 years

Step-by-step explanation:

7873.20=6250(1+8/100)n

7873.20=6250(1+2/25)n

7873.20/6250=(27/25)n

(27/25)³=(27/25)n

your answer is 3 years

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