Question

Q. Find the value of √28.8+ √72 + √43.2÷
√0.2 + √0.3 +√0.5

please tell me the answer of this Q #with explanation​

Answer 1

|| ✰✰ ANSWER ✰✰ ||

Values :-

√28.8 = 5.36

√72 = 8.48

✓43.2 = 6.57

√0.2 = 0.44

√0.3 = 0.54

√0.5 = 0.70

Now, let's solve this by using the values

√28.8+ √72 + √43.2 / √0.2 + √0.3 +√0.5

= 20.42 / 1.70

= 12 ( approx )

✪✪ Hence Answered ✪✪

Answer 2

Given to find,

$\displaystyle\longrightarrow\sf{x=\dfrac {\sqrt{28.8}+\sqrt{72}+\sqrt{43.2}}{\sqrt{0.2}+\sqrt{0.3}+\sqrt{0.5}}\quad\quad\dots (1)}$

We must see that,

• $\displaystyle\sf {\sqrt{28.8}=\sqrt{144\times0.2}}$

• $\displaystyle\sf {\sqrt{28.8}=\sqrt{144}\times\sqrt{0.2}}$

• $\displaystyle\sf {\sqrt{28.8}=12\sqrt{0.2}}$

And,

• $\displaystyle\sf {\sqrt{72}=\sqrt{144\times 0.5}}$

• $\displaystyle\sf {\sqrt{72}=\sqrt{144}\times \sqrt{0.5}}$

• $\displaystyle\sf {\sqrt{72}=12\sqrt{0.5}}$

And,

• $\displaystyle\sf {\sqrt{43.2}=\sqrt{144\times0.3}}$

• $\displaystyle\sf {\sqrt{43.2}=\sqrt{144}\times\sqrt{0.3}}$

• $\displaystyle\sf {\sqrt{43.2}=12\sqrt{0.3}}$

Hence (1) becomes,

$\displaystyle\longrightarrow\sf{x=\dfrac {12\sqrt{0.2}+12\sqrt{0.5}+12\sqrt{0.3}}{\sqrt{0.2}+\sqrt{0.3}+\sqrt{0.5}}}$

12 can be taken common in numerator.

$\displaystyle\longrightarrow\sf{x=\dfrac {12(\sqrt{0.2}+\sqrt{0.5}+\sqrt{0.3})}{\sqrt{0.2}+\sqrt{0.3}+\sqrt{0.5}}}$

Or,

$\displaystyle\longrightarrow\sf{x=\dfrac {12(\sqrt{0.2}+\sqrt{0.3}+\sqrt{0.5})}{\sqrt{0.2}+\sqrt{0.3}+\sqrt{0.5}}}$

$\displaystyle\longrightarrow\sf {\underline {\underline {x=12}}}$

Hence 12 is the answer.