Question

Q.Find the value of Cosec70° - sec20°

Please help me mates

Answer 1

Since we know that,

• cosec ∅ = 1/sin ∅
• sec ∅ = 1/cos ∅

→ cosec 70° - sec 20°

→ 1/sin 70° - 1/cos 20°

→ 1/sin 70° - 1/cos(90° - 70°)

Since we know that,

• cos(90° - ∅) = sin ∅

Hence, 1/sin 70° - 1/sin 70°

→ 0

Concepts

→ Trignometeric Relations

→ Breaking of angular terms

Answer – 0