Q) First term 1/3
common difference 1/2
find the arithmetic sequence.
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Step-by-step explanation:
Given a=1/3
d=1/2
a;a(1+d);a(2+d);a(3+d)
a(1+d)=1/3(1+1/2)
=1/3(3/2)
=3/6
a(2+d)=1/3(2+1/2)
=1/3(5/2)
=5/6
a(3+d)=1/3(3+1/2)
=1/3(7/2)
=7/6
so arthemathic sequence is 1/3 ;3/6;5/6;7/6
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