Question

Q) Five particles of mass 2 kg are attached to the rim of a circular disc of radius 0.1m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is

Answer 1

mass of disc is negligible,

mass of the system is 5×2=10 kg=M

moment of inertia is=Mr^2/2 (axis perpendicular to disc plane).

MI= 10 × 0.1×0.1/2

= 1/20=0.5kgm^2