Question

Q) Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu. How old are Nuri and Sonu?

Answer 1

According to Ques.

Let the present age of sonu be x

five year ago

sonu= (x-5) ------(1)

nuri = 3(x-5)-------(2)

ten years later

sonu= 10+x-------(3)

and nuri = 2(10+x) -------(4)

now we can say that.

on solving eq (1) and (2)

x-5= 3(x-5)

-5+15= 3x-x

10= 2x

x= 5

5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. Hence, age of Nuri = 50 years and age of Sonu = 20 years.

Answer 2

Answer:

Let the present age of Nuri  =x year

And present age of Sonu =y year

Five years ago

Age of Nuri =x–5years

Age of Sony =y–5years

Nuri was thrice as old as Sonu

X−5=3(y–5)

X–5=35–15

X–3y=−15+5

X–3y=−10                       ………..(1)

Ten years later,

Age of Nuri  =x+10

Age of Sonu =y+10

Nuri will be twice as old as Sonu.

X+10=2(y+10)

X+10=2y+20

X–2y=10                           ………..(2)

X–3y=−10                        ………..(1)

Subtracting equation (1) from equation (2)  we get

Y=20

Plug this value in equation first we get

X−3∗20=−10

X=60–10

X=50

Hence age  of Nuri =50 years and age of Sonu =20 years

hope it helps

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