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In triangle ABC, AB=3, BC=4 and AC=5, then find the radius of the circle touching the 3 sides of the circle.
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since it is a right triangle
Ac is the dia of the circle bcz dia. subtend 90° in the semicircle so radius is 5/2=2.5
Ac is the dia of the circle bcz dia. subtend 90° in the semicircle so radius is 5/2=2.5
prateiklohani:
sorry the circle is in the triangle
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