Q. For practical purpose, the average atomic mass of oxygen (which is an isotopic mixture of ¹⁶o ¹⁷0 and ¹⁸0) is assumed to be equal to (A) 15.0 u (B) 16.0 u (C) 17.0 u (D) 18.0 u
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Answer:
16.0 u
Explanation:
According to available data :
Average atomic mass of oxygen =16×0.9976+17×0.0004+18×0.002
=15.9616+0.0068+0.036=16.004u.
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