Q. for the curve √x + √y = 1 , DY/ DX at (1/9, 1/9) is
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d(√x+√y) /dx=d(1) /dx
(1/2√x) +(1/2√y) *dy/dx=0
(1/2√y) *dy/dx=-1/2√x
-dy/dx=√y/√x
dy/dx=-√y/√x
dy/dx=-√(1/9) /√(1/9) =-1
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