Question

Q) For
the
network shown
in the figure,
the value of current flowing in the 5ohm resistor will be?​

Answer 1

Answer:

ANSWER

This is a Wheatstone bridge circuit. here four arms resistances , P=4Ω,Q=2Ω,R=6Ω,S=3Ω

since,

Q

P

=

S

R

so it is in balanced condition and no current flow the middle resistance 4Ω. Thus, it is removed from circuit.

Now equivalent resistance of the circuit is R

eq

=(4+2)∣∣(6+3)=6∣∣9=

6+9

6×9

=54/15=18/5Ω

Current, i=V/R

eq

=5V/18