Math, asked by aspirant007, 7 months ago

Q.For the sample values of 1,3,5,7,9. What is the Standard Error of the sample mean ?

Answers

Answered by Ronak0349
0

ANS:

(A) 95% confidence interval for µnormal = (sample mean) ± t(n-1, .975)(sem) = 1.35 ± t(39,.975)(0.5/sqrt(40)) = 1.35 ± (2.02)(0.079) = 1.35 ± 0.16 = (1.19, 1.51)

(B) 95% confidence interval for µnormal = 0.92 ± t(31, .975)(0.4/sqrt(32)) = 0.92 ± (2.04)(0.071) = 0.92 ± 0.14 = (0.78, 1.06)

(C) Since the confidence intervals do not overlap, we may be confident that the population means different

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Answered by ItzDeadDeal
1

ANS:

(A) 95% confidence interval for µnormal = (sample mean) ± t(n-1, .975)(sem) = 1.35 ± t(39,.975)(0.5/sqrt(40)) = 1.35 ± (2.02)(0.079) = 1.35 ± 0.16 = (1.19, 1.51)

(B) 95% confidence interval for µnormal = 0.92 ± t(31, .975)(0.4/sqrt(32)) = 0.92 ± (2.04)(0.071) = 0.92 ± 0.14 = (0.78, 1.06)

(C) Since the confidence intervals do not overlap, we may be confident that the population means different

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