Question

Q) Four springs are connected as shown in figure,
and under the action of applied force the system is
in a state of equilibrium. Find the ratio of
extensions developed in springs,
X1:X2:X3..?

plz help me to solve this ASAP!!!​

Answer 1

Answer:

answer is the  3rd option ................

Explanation:

Answer 2

Answer:

The ratio of extensions Δx₁ : Δx₂ : Δx₃ = 3 : 6 : 2.

Explanation:

We know that extension in the spring 1 is Δx₁ = F/K₁

If the force (F) is acting on the spring 1 then the force acting on the springs 2, 3, 4 will be equal and has a value of 2F, because they are connected in series.

So, the extension in the spring 2 is Δx₂ = 2F/K₂

Extension in the spring 3 is Δx₃ = 2F/K₃

Extension in the spring 4 is Δx₄ = 2F/K₄

Now the ratio Δx₁ : Δx₂ : Δx₃ = F/K₁ : 2F/K₂ : 2F/K₃

                                               = F/K : 2F/K : 2F/3K

                                               = 1 : 2 : 2/3

                                               = 3 : 6 : 2

Therefore, the ratio of extensions Δx₁ : Δx₂ : Δx₃ = 3 : 6 : 2

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