Q. From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameteris cut off. Find the area of remining paper (use π = 22/7)
Answers
Answer:
Length of paper, AB = l = 40cm
Width of paper, AD = b = 28cm
Area of paper = l × b = 40 × 28 = 1120 cm2
Diameter of semi-circle = 28cm
∴ Radius of semi-circle, r = 14cm
Thus, area of semi-circle = 1/2. πr2
= 1/2 × 22/7 × 14 × 14
= 308cm2
∴ Area of remaining paper = 1120 – 308 = 812 cm2
Answer:
Length of paper, AB = l = 40cm
Width of paper, AD = b = 28cm
Area of paper = l × b = 40 × 28 = 1120 cm²
Diameter of semi-circle = 28cm
∴ Radius of semi-circle, r = 14cm
Thus, area of semi-circle = 1/2 πr²
= 1/2 × 22/7 × 14 × 14
= 308 cm²
∴ Area of remaining paper = 1120 – 308
= 812 cm²