Math, asked by admire29, 10 months ago

Q. From a rectangular sheet of paper ABCD with AB = 40 cm and AD = 28 cm, a semi-circular portion with BC as diameteris cut off. Find the area of remining paper (use π = 22/7)​

Answers

Answered by ItzLava90
2

Answer:

Length of paper, AB = l = 40cm

Width of paper, AD = b = 28cm

Area of paper = l × b = 40 × 28 = 1120 cm2

Diameter of semi-circle = 28cm

∴ Radius of semi-circle, r = 14cm

Thus, area of semi-circle = 1/2. πr2

= 1/2 × 22/7 × 14 × 14

= 308cm2

∴ Area of remaining paper = 1120 – 308 = 812 cm2

Answered by lolwa6
0

Answer:

Length of paper, AB = l = 40cm

Width of paper, AD = b = 28cm

Area of paper = l × b = 40 × 28 = 1120 cm2

Diameter of semi-circle = 28cm

∴ Radius of semi-circle, r = 14cm

Thus, area of semi-circle = 1/2. πr2

= 1/2 × 22/7 × 14 × 14

= 308cm2

∴ Area of remaining paper = 1120 – 308 = 812 cm2

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