Question

Q. Froma right circular cylinder of radius 7 cm, height 24cm of conical cavity of same base radius and of same height hollowed out. find the volume and whole surface of remaining solid .

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Answer 1

Answer:

Given,

height (h) of the conical part = height (h) of the cylinder part = 24 cm

radius (r) of the cylinder part = 7 cm

$slant \: \: height \: (l) \: of \: \: conical \: part = \sqrt{r {}^{2} + h {}^{2} } \\ \sqrt{(7) {}^{2} + (24) {}^{2} } = \sqrt{49 + 576 } \\ = \sqrt{625} = 25$

total surface area of the remaining solid will be

=CAS of cylindrical part + CAS of conical part + Area of cylindrical base

$2\pi \: rh + \pi \: rh + \pi \: r {}^{2}$

2 × 22/7 × 7 × 24 + 22/7 × 7 × 25 + 22/7 × 7 × 7

44 × 24 + 22 × 25 × 22 × 7

=1056 + 550 + 157 = 1760 cm²

the total surface area of the remaining solid is 1760 cm²

Answer 2

Answer:

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