Question

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Q--ωнατ ωιℓℓ ϐє τнє ϲнαиgє ιи κιиєτιϲ єиєяgγ ιƒ τнє мαѕѕ ιѕ нαℓƒє∂ αи∂ νєℓοϲιτγ ιѕ ∂ουϐℓє∂? 

✔Elaborate the answer ✔

❌N̸O̸ S̸P̸A̸M̸M̸I̸N̸G̸ ❌

Answer 1

$kinetic \: energy \: = 1 \div 2 \times m \times v^{2}$
when m = 1/2
and velocity v =2
then
$ke \: = 1 \div 2 \times m \div 2 \times (2v) ^{2}$
$m \div 4 \times 4v^{2}$
4 cut by 4 so it remains
$mv^{2}$
so it becomes 2 times than the real one
it is your answer

Answer 2

kinetic energy= 1/2 mv^2

when mass is halfed and velocity is doubled
therefore m=m/2 and v =2v

then the kinetic energy will be → 1/2*m/2*(2v)^2
=m/4*4v^2
=mv^2

hence the new kinetic energy will be double of the previous one.


hope it helps you