Question

Q: given that 5 cos ² x - 2 sin x - 2 =0, then value of cot x/2 i will mark you brainliest i promise

Answer 1

4cotx=3

therefore cotx=3/4

cot=adj/opp

ac^2=ab^2+bc^2

ac^2=4^2+3^2

ac^2=16+9

ac^2=25

ac=5

sinx=opp/hyp=4/5

cosx=adj/hyp=3/5

(sinx-cosx)(sinx+cosx)

4/5-3/5×4/5+3/5

1/5×7/5

$= \frac{7}{25}$

Answer 2

Answer:

$\huge\underline\bold\red{AnswEr}$

4cotx=3

therefore cotx=3/4

cot=adj/opp

ac^2=ab^2+bc^2

ac^2=4^2+3^2

ac^2=16+9

ac^2=25

ac=5

sinx=opp/hyp=4/5

cosx=adj/hyp=3/5

(sinx-cosx)(sinx+cosx)

4/5-3/5×4/5+3/5

1/5×7/5

$\begin{lgathered}= \frac{7}{25} \\\end{lgathered}$