༻ᴀɴꜱᴡᴇʀ ᴛʜᴇ Qᴜᴇꜱᴛɪᴏɴ ɢɪᴠᴇɴ ɪɴ ᴛʜᴇ ᴀᴛᴛᴀᴄʜᴍᴇɴᴛ
༻ꜱᴜʙ:ᴍᴀᴛʜꜱ
༻grade :9ᴛʜ
༻dᴏɴ'ᴛ ᴅᴀʀᴇ ᴛᴏ ꜱᴘᴀᴍ
the answer must include the steps of solution .
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Answered by
6
Answer:
your question is to find the zeroes of the polynomial
{x}^{2} - 3x - 4x2−3x−4 =0
{x}^{2} - x + 4x - 4x2−x+4x−4 =0
x (x-1)+4 (x-1)=0
(x-1)(x+4)=0
(x-1)=0 (x+4)=0
x=1 or x=(-4)
Answered by
19
Answer:
x^+3x−4=0
x ^{2} + (4 - 1)x - 4 = 0x
2
+(4−1)x−4=0
x ^{2} + 4x - x - 4 = 0x
2
+4x−x−4=0
x(x + 4) - 1(x + 4) = 0x(x+4)−1(x+4)=0
(x - 1)(x + 4) = 0(x−1)(x+4)=0
eithereither
x - 1 = 0x−1=0
x = 1x=1
oror
x + 4 = 0x+4=0
x = - 4x=−4
hope it helps
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