Question

Q => A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.​

Answer 1

HERE IS YOUR ANSWER MATE.....;

Given,

Length of the vertical pole = 6 m

Shadow of the pole = 4 m

Let the height of the tower be h m.

Length of the shadow of the tower = 28 m

Class 10 Maths Chapter 6 Triangles 04

In ΔABC and ΔDFE,

∠C = ∠E (angle of elevation)

∠B = ∠F = 90°

By AA similarity criterion,

ΔABC ~ ΔDFE

We know that the corresponding sides of two similar triangles are proportional.

AB/DF = BC/EF

6/h = 4/28

h = (6 ×28)/4

h = 6 × 7

h = 42

Hence, the height of the tower = 42 m

Hope It's Helpful....:)

@ItzPsycho17

Answer 2

❤[Answer]❤

Let AB a pole and DE be a tower. Bc is the shadow of the pole such that BC => 4m. It is given that, height of pole (AB) => 6m.

Let EF is the shadow of the tower DE such that EF => 28m.

Let height of the tower be 4m.

In Triangle ABC and triangle DEF we have

/ B = / E (90°)

/ A = / D

[Therefore, shadow are case at the same rate]

Therefore, by using AA similar condition

/\ ABC ~ /\ DEF

$= > \frac{ab}{de} = \frac{bc}{ef}$

[Propotional sides of two similar triangle]

$= > \frac{6}{h} = \frac{4}{28}$

$= > 4h = 28 \times 6$

$= > h = 42$

Hence, the height of the tower is 42m.

Hope it helps you dear❣❣

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