Question

Q =>
$x {}^{2} + 2x + 1$
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Answer 1

HERE IS YOUR ANSWER MATE.....;

$= > x {}^{2} + 2x + 1 = 0$

$= > x {}^{2} + x + x + 1 = 0$

$= > x(x + 1) + 1(x + 1) = 0$

$= > (x + 1)(x + 1) = 0$

$x = - 1$

$x = - 1$

HOPE IT'S HELPFUL....:-)

Answer 2

$\huge\bold{\underline{\underline{Answer}}}$

$\implies {x}^{2} + 2x + 1 = 0$

$\implies {x}^{2} + 1x + 1x + 1 = 0$

$\implies \: x(x + 1) + 1(x + 1) = 0$

$\implies(x + 1)(x + 1) = 0$

$\implies(x + 1) = 0 \: or \: (x + 1) = 0$

$\implies \: x = - 1 \: or \: x = - 1$