Question

Q) he angles of a triangle are in the ratio 1:3:5. Find the measure of each of the angles.

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Answer 1

A N S W E R :

• 1st angle x = 20°

• 2nd angle 3x = 60°

• 3rd angle 5x = 100°

Given :

• Angle of a triangle are in the ratio 1:3:5

To find :

• Find the measure of each angle ?

Solution :

• Let be x the common in given ratio,

As we know that,

• Sum of all angle of triangle = 180°

=> 1st angle = x°

=> 2nd angle = 3x°

=> 3rd angle = 5x°

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=> 1st + 2nd + 3rd = 180°

=> x + 3x + 5x = 180°

=> 9x = 180°

=> x = 180/9

=> x = 20°

Now, the measure of

=> 1st angle x = 20°

=> 2nd angle 3x = 30°

=> 3rd angle 5x = 100°

V E R I F I C A T I O N :

=> 20° + 60° + 100° = 180°

=> 180° = 180°

Answer 2

Question :-

• The angles of a triangle are in the ratio 1:3:5. Find the measure of each angle.

Answer :-

Given :-

• Angels of the triangle are in the ratio 1:3:5.

To Find :-

• Find the measure of each angle.

Solution :-

• Let the first angle be x
• Let the second angle be 3x
• Let the third angle be 5x

• As we know that the sum of all angles of a triangle is 180°

So,

• x + 3x + 5x = 180° (Angle sum property)
• 9x = 180°
• x = 180°/9
• x = 20°

Therefore,

• First angle = x = 20°
• Second angle = 3x = 3×20° =60°
• Third angle = 5x = 5×20° = 100°

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