Question

Q. How many gram of oxygen (02) is required to completely react with 0.200 g of hydrogen (H2) to
yield water (H2O)? Also calculate the amount of water formed. (molecular mass H = 2, O = 32)​

Answer 1

Answer:

1.6 gms

Explanation:

no. of moles of H =0.200/1

no. of moles of O2 used =1/2*no. of moles of H2(by reaction)

no. of moles of O2=0.100

weight of oxygen=0.100*16

=1.6 gms

amount of water formed =moles of H2 used *18

=0.200*18

=3.6 gms