Q. How many gram of oxygen (02) is required to completely react with 0.200 g of hydrogen (H2) to
yield water (H2O)? Also calculate the amount of water formed. (molecular mass H = 2, O = 32)
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Answer:
1.6 gms
Explanation:
no. of moles of H =0.200/1
no. of moles of O2 used =1/2*no. of moles of H2(by reaction)
no. of moles of O2=0.100
weight of oxygen=0.100*16
=1.6 gms
amount of water formed =moles of H2 used *18
=0.200*18
=3.6 gms
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