Question

Q) How many spherical bullets can be made out of a solid cube of lead whose edge measures 44 cm ,each bullet being radius 4 cm in diameter?

Answer 1

Diameter of sphere 4cm

Radius 2cm

Volume of sphere = 4/3×22/7×2^3

=33.52cm^3

Edge of cube 44cm

Volume of cube= 44×44×44=85184cm^3

Number of lead shots= 85184/33.52

= 2541

Hope it helps..!

Answer 2

HEY MATE

$\huge\mathfrak\red{Solution}$

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The volume of cube

$= 44 \times 44 \times 44 {cm}^{3}$

$the \: no \: of \: bullets = \frac{vol \: of \: cube}{vl \: of \: spherical \: bullet}$

$= \frac{44 \times 44 \times 44}{ \frac{4}{3} \times \frac{22}{7} \times 2 \times 2 \times 2 }$

$\frac{44 \times 44 \times 44}{ \frac{4 \times 22 \times 2 \times 2 \times 2}{21} } = \frac{44 \times 44 \times 44 \times 21}{4 \times 22 \times 2 \times 2 \times 2} = 2541$

therefore, 2541 bullets will be made by this

$<b><I><u>$

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