Question

Q) How many three digit number are there which leaves a reminder 3 on division by 7.
Answer this question step by step explanation.​​

Answer 1

Step-by-step explanation:

First three digit number that leaves a remainder 3 on division by 7 is 101

last three digit number that leaves a remainder 3 on division by 7 is 997

AP - 101, 108, 115.........997

Let n be the number of terms

common difference=108-101=7

Last term = first term +(n-1)common difference

997=101 +(n-1)*7

997-101=(n-1)*7

896= (n-1)*7

896/7=(n-1)

128=n-1

129=n

therefore 129 three digit numbers are there which leave a remainder 3 on division by 7