Math, asked by preetisree15rs, 2 months ago

Q- how much smaller than 2a+4b-c is 5a -3b +2c

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Answers

Answered by sushilsharma49808
0

Step-by-step explanation:

ax

2

+bx+c=0, where a

=0.

Condition for real roots of a quadratic equation is b

2

≥4ac. This condition has

to be true. As for the second condition to be true, all coefficient should be

positive.

The proof is easy. If you know a little calculus then you can find that a quadratic

function reaches its extremum when x=

2a

−b

. This result can be derived via

rearranging the terms in the form of a(x+p)

2

+q. Also we know that the

extremum is always halfway between the two roots. So when both of the roots

are negative then the extremum should also be negative.

2a

b

<0

or,

a

b

>0

or,

a

2

ab

>0

or, ab>0.

So both a and b should have same sign. Without loss of generality it would be

safe to assume that both a and b is positive (if they were negative then multiply

the quadratic by (-1)). The general from of the roots are

x=

2a

−b±

b

2

−4ac

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