Question

Q. How to calculate log(0.12)

Answer 1

Log A * B = Log A + Log B

LogA /B = Log A - Log B

Now,
Log ( 0. 12 ) = Log ( 12 / 100 )

= Log 12 - Log 100

= Log (3 * 4 ) - Log (10)²

= Log 3 + Log 4 - 2 Log 10

= Log 3 + Log 2 ² - 2 Log 10

= Log 3 + 2 Log 2 - 2 Log 10

= 0.477 + 2 ( 0. 301 ) - 2 * 1

= 0.477 + 0. 602 - 2

= - 0. 921