Question

Q. i) An object of height 8 cm is placed at a distance of 25 cm in front of a lens having radius of curvature 30 cm The image of an object is obtained on the screen. Determine the nature of lens used. Also find the nature, size and position of image formed. ​

Answer 1

Explanation:

Mirror formula :

v

1

+

u

1

=

f

1

...........(1)

So, u=−27cm

Concave mirror have negative focal length.

f=−18cm

Putting the values in (1),

v

1

+

−27

1

=

−18

1

We get , v=−54cm

Also,

Magnification =

h

1

h

2

=

u

−v

7.0

h

2

=−

−27

−54

h

2

=−14.0cm

Image will be real and inverted and will be of size 14 cm