Question

Q.
i) x+y + √2 = 0
ii) √3-y+2=0
Turn The Equation into Normal form.
(Co-ordinate Geometry)
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Answer 1

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1. x + y + √2

• x + y + √2 = 0 ----(1)

• ± (√a² + b²) = ±(√ 1 + 1)

• = ±√2

Now , divide by ±√2

x/±√2 + y/±√2 = -√2/±√2

x/-√2 + y/-√2 = 1

2. √3 - y + 2 = 0

• ±(√a² + b²) = ±(√3 + 1)

• ±√4 = ±2

Now , divide by ±2

• √3/-2 x + 1/±2y = -2/±2

• √3/-2x + 1/-2y = -2/-2

• (√3/-2)x + ½y = 1