Q. If 13 sinA = 5, A is a acute angle find 5sinA-2cosA/tanA
Please ans me this question
Answers
Answered by
2
Answer:
(5sinA-2cosA)/tanA
=(5×5/13 - 2×12/13)5/12
=(25/13 - 24/13)5/12
=(1/13)/(5/12)
=(1×12)/(13×5)
=12/65
Answered by
0
Answer:
sinA=5/13,cosA=12/13,and tanA=5/12
so 5sinA-2cosA/tanA becomes
5(5/13)-2(12/13)(12/5)
25/13-288/65
125/65-288/65
-163/65 us the correct ans for ur QUESTION
Step-by-step explanation:
please mark my ans as brainliest please
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