Math, asked by infernapeshashank, 2 months ago


Q. If 13 sinA = 5, A is a acute angle find 5sinA-2cosA/tanA

Please ans me this question​

Answers

Answered by Anonymous
2

Answer:

(5sinA-2cosA)/tanA

=(5×5/13 - 2×12/13)5/12

=(25/13 - 24/13)5/12

=(1/13)/(5/12)

=(1×12)/(13×5)

=12/65

Answered by Anonymous
0

Answer:

sinA=5/13,cosA=12/13,and tanA=5/12

so 5sinA-2cosA/tanA becomes

5(5/13)-2(12/13)(12/5)

25/13-288/65

125/65-288/65

-163/65 us the correct ans for ur QUESTION

Step-by-step explanation:

please mark my ans as brainliest please

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