Question

Q). If [{(2x + 2)(x + 3)} + 8) = (2x + 1) (x + 5), then find out the value of x ?

(a) 3
(b) 1
(c) 2
(d) 8​

Answer 1

Answer:

hey there!

hope this helps u

Answer 2

$\large\pmb{\frak{\underline{Answer~:}}}$

Option a)

3 is correct Option

Given:-$\qquad{\sf:\implies{\bigg[ \bigg\{ \bigg(2x~+~2\bigg)\bigg(x~+~3\bigg)\bigg\}~+~8\bigg]~=~\bigg(2x~+~1\bigg)~\bigg(x~+~5\bigg)}}$

To Find : Find the Value of x ?

_________________________

Solution : Here in this question, we are provided with a equation and we are asked to solve that equation to find the value of x, let's start solving our equation and understanding the steps to get our value of x.

$\qquad{\sf:\implies{\bigg[ \bigg\{ \bigg(2x~+~2\bigg)\bigg(x~+~3\bigg)\bigg\}~+~8\bigg]~=~\bigg(2x~+~1\bigg)~\bigg(x~+~5\bigg)}}$

$\qquad{\sf:\implies{\bigg(2x~+~2\bigg)\bigg(x~+~3\bigg)~+~8~=~\bigg(2x~+~1\bigg)\bigg(x~+~5\bigg)}}$

$\qquad{\sf:\implies{2x^2~+~8x~+~6~+~8~=~\bigg(2x~+~1\bigg)\bigg(x~+~5\bigg)}}$

$\qquad{\sf:\implies{2x^2~+~8x~+~14~=~\bigg(2x~+~1\bigg)\bigg(x~+~5\bigg)}}$

$\qquad{\sf:\implies{2x^2~+~8x~+~6~+~8~=~2x^2~+~11x~+~5}}$

$\qquad{\sf:\implies{2x^2~-~2x^2~+~8x~+~14~=~11x~+~5}}$

$\qquad{\sf:\implies{8x~+~14~=~11x~+~5}}$

$\qquad{\sf:\implies{8x~-~11x~=~5~-~14}}$

$\qquad{\sf:\implies{- 3x~=~5~-~14}}$

$\qquad{\sf:\implies{- 3x~=~- 9}}$

$\qquad{\sf:\implies{3x~=~9}}$

$\qquad:\implies{\underline{\boxed{\frak{\pink{x~=~3}}}}}$

Hence,

$\therefore\underline{\sf{The~ value ~of~x~is~\bf{\underline{3}}}}$