Question

Q. IF 3=237x + 81y, FIND THE VALUE OF X&Y, WHERE IS 3 IS THE HCF. ​

Answer 1

Answer:

HEYY...

Step-by-step explanation:

By Euclid's Division Algorithm,

237=81(2)+(75).....(1)

81=75(1) + (6).....(2)

75=6(12)+(3).....(3)

6=3(2)+(0)

HCF =3

Expressing it in the form of 237x+81y=HCF

3=75-6(12).......from(3)

3=75-(81-75)(12)......from(2)

3=75-(81×12-75×12)

3=75-81×12+75×12

3=75(13)-81(12)

3=(237-81×2)(13)-81(12).....from(1)

3=237(13)-81(38)

3=237(13)+81(-38)

Therefore, x =13 , y =- 38

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Answer 2

Answer:

hi ARMY how are u

Step-by-step explanation:

purple u