Question

Q. If 6sin^2theta-11sin theta+4=0​

Answer 1

Answer:

6sin^2\theta-11sin\theta+4=0\\\\6sin^2\theta-8sin\theta-3sin\theta+4=0\\\\2sin\theta(3sin\theta-4)-1(3sin\theta-4)-=0\\\\(2sin\theta-1)(3sin\theta-4)=0\\\\sin\theta=\frac{1}{2},\:\frac{4}{3}

But,\: -1\leq\:sinx\:\leq\:1

Therefore,

sin\theta=\frac{1}{2}

Step-by-step explanation:

Answer 2

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