Question

Q. If a body starts from rest, the time in which it covers a particular displacement with uniform acceleration is

Answer 1

Explanation:

if a body starts from rest the time in which it covers a particular displacement with uniform acceleration is directly proportional to the square root of the displacement hope it helps u bro

Answer 2

Answer:

Concept:

If a body starts from rest, the time in which it covers a particular displacement with uniform acceleration is directly proportional to the square root of the displacement.

Explanation:

By applying the equation of kinematic

$\begin{aligned}&\mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at} \mathrm{t}^{2} \\&\mathrm{t}^{2}+\frac{2 \mathrm{ut}}{\mathrm{a}}-\frac{2 \mathrm{~s}}{\mathrm{a}}=0 \\&\mathrm{t}^{2}+\mathrm{pt}-\mathrm{ks}=0 \\&\mathrm{Where}, \mathrm{p}=\frac{2 \mathrm{u}}{\mathrm{a}} \text { and } \mathrm{k}=\frac{2}{\mathrm{a}} \\&\mathrm{t}=\frac{-\mathrm{p} \pm \sqrt{\mathrm{p}^{2}+\mathrm{ks}}}{2}\end{aligned}$

So, time is directly proportional to the root of displacement.

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