Question

Q. If a bus travelling at 20 m/s is subjected to a steady deceleration of 5 m/s square . How long will it take to come to rest?

Answer 1

Given :

Initial velocity (u) = 20 m/s

Final velocity (v) = 0 m/s

Acceleration (a) = – 5 m/s2

a= v-u/t

Now, Time taken t = v – u / a

 t = 0 – 20/– 5 = 4 sec

Answer 2

Apply the third equation of uniformly accelerated motion

Which is

v²-u²=2aS

Where v is final velocity

u is initial velocity

a is acceleration

Ans S is displacement

v=0

u=20m/s

a=-5m/s²

S=?

0²-20²=2(-5)(S)

-400/-10=S

40m

40m is your answer

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