Question

Q- If a line has the direction ratios –18, 12, –4, then what are its direction cosines?(Please dont answer wrong)


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Answer 1

Answer:

$\huge{\bf{\underline{\red{Answer :}}}}$

Directions ratios of the line are –18, 12, –4,$\sqrt{(-18)² + (12)² + (-4)²}$

$\Rightarrow$Dividing Each

$\Large\sqrt{{(-18)}^{2} + {(12)}^{2} + {(-4)}^{2}}$

$= \Large \sqrt{324 + 144 + 16}$

$= \Large \sqrt{484}$

$= \Large22$

$\Rightarrow$The Direction cosines of the line are

$\Large - \frac{19}{11} , \frac{6}{11} and \: \frac{ - 2}{12}$

Answer 2

❥Answer:-

Directions of ratios of the line are -18, 12, -14

$\sqrt{ {( - 18)}^{2} + {(12)}^{2} + {( - 4)}^{2} }$

===> Dividing Each

$\sqrt{ {( - 18)}^{2} + {(12)}^{2} + {( - 4)}^{2} }$

$\sqrt{324 + 144 + 16}$

$\sqrt{148}$

==> The direction cosines of the line are

$- \ \frac{19}{11} \: \: \: \frac{6}{11 \:} and \frac{ - 2}{12}$