Q. If active mass of a 6 percent solution of a compound is 2, it's molecular weight will be <br />a. 30. b. 15<br />c.60. d. 22
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Answered by
13
6% of solution contains 6g of compound in 100ml of solution.
Mass of compound present in 1 liter of solution = 60g
Concentration = Moles/liter
= 60/Molar mass
Given active mass = 2
So, 60/Molar mass = 2
=> Molar mass = 30
Ans: Option a. 30
Mass of compound present in 1 liter of solution = 60g
Concentration = Moles/liter
= 60/Molar mass
Given active mass = 2
So, 60/Molar mass = 2
=> Molar mass = 30
Ans: Option a. 30
Answered by
7
heya......
A 6% solution contains 6 g of the compound in 100 ml of solution.
Mass of compound present in 1 litre of solution = 6o g
Let M be the molar mass.
Concentration = 60 g/litre = (60/M) moles/litre
Active mass(given) = 2
Therefore, 60/M = 2
Molar mass M = 60/2 = 30.
tysm..#gozmit
A 6% solution contains 6 g of the compound in 100 ml of solution.
Mass of compound present in 1 litre of solution = 6o g
Let M be the molar mass.
Concentration = 60 g/litre = (60/M) moles/litre
Active mass(given) = 2
Therefore, 60/M = 2
Molar mass M = 60/2 = 30.
tysm..#gozmit
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